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.5x^2-2x-2.5=0
a = .5; b = -2; c = -2.5;
Δ = b2-4ac
Δ = -22-4·.5·(-2.5)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-3}{2*.5}=\frac{-1}{1} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+3}{2*.5}=\frac{5}{1} =5 $
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